Re: [PrototypeRoot]

 On Sat, 20 Jun 2009, Cameron McCormack wrote: > > Ian Hickson: > > I don't really mind exactly what the solution is; my only concern here  > > would be that I'd be throwing [PrototypeRoot] around a lot. >  > Acknowledged.  If you can propose a way of defining this without needing > to use [PrototypeRoot] a lot, that’d help.  Given an object and a list of interface that it implements, remove  interfaces from the list that match any of the following conditions:    - the interface was on the right hand side of an 'implements' clause the      left hand side of which lists an interface that the object implements    - the interface is inherited from another interface the object      implements    - the interface has [NoInterfaceObject]  ...you should be lift with one interface. Use its name as the [[Class]].  Are there any objects where that leaves an ambiguity?  --  Ian Hickson               U+1047E                )\._.,--....,'``.    fL http://ln.hixie.ch/       U+263A                /,   _.. \   _\  ;`._ ,. Things that are impossible just take longer.   `._.-(,_..'--(,_..'`-.;.'